Match List I (Oxdiation number) with List II (The element) and select the correct answer using the codes given below this lists

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Q: 110 (IAS/2002)
Match List I (Oxdiation number) with List II (The element) and select the correct answer using the codes given below this lists
(Oxidation number)(The element)
A. 21. Oxidation number of Mn in MnO2
B. 32. Oxidation number of S in H2S2O7
C. 43. Oxidation number of Ca in CaO2
D. 64. Oxidation number of Al in NaAIH4

question_subject: 

Science

question_exam: 

IAS

stats: 

0,9,8,9,5,2,1

keywords: 

{'oxdiation number': [0, 0, 1, 0], 'element': [0, 0, 0, 1]}

Explanation: The way to approach this question is by understanding the oxidation number associated with each element in the compounds mentioned.

In the given answer, A-3 matches oxidation number 2 with Calcium in CaO2 which is correct since Calcium typically has an oxidation number of +2. B-4 Matches oxidation number 3 with Aluminum in NaAlH4. In this compound, Aluminum indeed has an oxidation number of +3. C-1 matches oxidation number 4 with Manganese in MnO2, which is correct as Manganese has +4 oxidation state in this compound. Lastly, D-2 matches oxidation number 6 with Sulfur in H2S2O7 where Sulfur has +6 oxidation state.

So the correct matching is A-3 (2 with Calcium), B-4 (3 with Aluminum), C-1 (4 with Manganese), D-2 (6 with Sulfur) and therefore, option 1 is the correct answer.

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