The monthly income of Komal and Asha are in the ratio of 4 : 3. Their monthly expenses are in the ratio of 3 : 2. However, both save Rs. 600 per month. What is their total monthly income ?

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Q: 131 (IAS/2000)
The monthly income of Komal and Asha are in the ratio of 4 :
3. Their monthly expenses are in the ratio of 3 :
2. However, both save Rs. 600 per month.
What is their total monthly income ?

question_subject: 

Maths

question_exam: 

IAS

stats: 

0,4,6,3,3,4,0

keywords: 

{'total monthly income': [0, 1, 0, 0], 'monthly income': [0, 0, 1, 0], 'ratio': [1, 0, 1, 12], 'monthly expenses': [0, 1, 0, 0], 'komal': [0, 1, 0, 0], 'asha': [0, 1, 1, 2]}

Let`s assume that the monthly income of Komal is 4x and the monthly income of Asha is 3x. Similarly, let`s assume that the monthly expenses of Komal is 3y and the monthly expenses of Asha is 2y.

Given that both Komal and Asha save Rs. 600 per month, we can write the equation:

Income - Expenses = Savings

For Komal:

4x - 3y = 600

For Asha:

3x - 2y = 600

We need to find the value of x, which represents the total monthly income of Komal and Asha.

To solve these equations, we can use the method of substitution. From the first equation, we can express y in terms of x:

y = (4x - 600) / 3

Substituting this value of y into the second equation, we get:

3x - 2((4x - 600) / 3) = 600

Simplifying the equation, we get:

9x - 8x + 1200 = 1800

x + 1200 = 1800

x = 600

Now we can calculate the total monthly income by substituting the value of x into the equation:

Total monthly income = Komal`s income + Asha`s income

= 4x + 3x

= 7x

= 7 * 600

= Rs. 4,200

Therefore, the total monthly income of Komal and Asha is Rs. 4,200. The correct answer is option C.

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