The number of ways in which 3 boys and 2 girls can he arranged in a queue, given that the 2 girls have to be next to each other, is

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Q: 56 (CAPF/2018)
The number of ways in which 3 boys and 2 girls can he arranged in a queue, given that the 2 girls have to be next to each other, is

question_subject: 

Maths

question_exam: 

CAPF

stats: 

0,12,9,1,6,12,2

keywords: 

{'queue': [0, 0, 0, 1], 'girls': [0, 2, 3, 10], 'number': [0, 0, 0, 2], 'boys': [0, 1, 5, 11]}

The correct answer is option 3, which is 48.

To arrange the 3 boys and 2 girls in a queue with the condition that the 2 girls have to be next to each other, we can treat the 2 girls as a single entity. This means that we have 4 entities to arrange: 3 boys and the "group" of 2 girls.

The 4 entities can be arranged in 4! (4 factorial) ways. However, within the "group" of 2 girls, the girls can be arranged in 2! (2 factorial) ways.

Thus, the total number of ways to arrange them is 4! * 2!, which is equal to 24 * 2 = 48.

Therefore, the correct answer is option 3, which is 48.

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