Solve the given equations : x^2 + y^2 = 34 x^4 - y^4 = 544 The values of x and y are

examrobotsa's picture
Q: 139 (IAS/2001)
Solve the given equations : x^2 + y^2 = 34
x^4 - y^4 = 544 The values of x and y are

question_subject: 

Maths

question_exam: 

IAS

stats: 

0,3,0,0,3,0,0

keywords: 

{'equations': [0, 0, 1, 1], 'values': [0, 2, 1, 3]}

The first equation, x^2 + y^2 = 34, signifies the sum of squares of x and y is 34. And the second equation, x^4 - y^4 = 544, where the fourth power of x is larger than that of y by 544. From the options, we have numbers and their negative counterparts. First, let`s exclude option 4 as sum of squares for 3 and 4 is 25, not 34. Next, option 1 and 3 can also be eliminated as their fourth power differences isn`t 544. So, we are left with option 2. Squaring 5 and 3 indeed gives us 34 and the difference between their fourth powers equals 544. Therefore, the correct answer is option 2 (+/-5, +/-3) because it rightly satisfies both the equations.

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