Two metallic wires A and B are made using copper. The radius of wire A is r while its length is l. A dc voltage V is applied across the wire A, causing power dissipation, P. The radius of wire B is 2r and its length is 2l and the same dc voltage V is appl

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Q: 46 (NDA-I/2019)
Two metallic wires A and B are made using copper. The radius of wire A is r while its length is l. A dc voltage V is applied across the wire A, causing power dissipation, P. The radius of wire B is 2r and its length is 2l and the same dc voltage V is applied across it causing power disspation P
1.
Which one of the following is the correct relationship between P and P1?

question_subject: 

Science

question_exam: 

NDA-I

stats: 

0,0,1,1,0,0,0

The correct relationship between P and P1 can be determined by examining the factors that contribute to power dissipation in a metallic wire. Power dissipation in a wire is given by the equation P = (V^2) / R, where V is the voltage applied across the wire and R is its resistance.

Comparing wire A and wire B, we can see that wire B has twice the radius and twice the length of wire A. The resistance of a wire is inversely proportional to its cross-sectional area, which is proportional to the square of its radius. Therefore, the resistance of wire B is (2r)^2/(r^2) = 4.

Now, considering the equation for power dissipation, we can see that the resistance of wire B is four times that of wire A. When the same voltage V is applied across both wires, the power dissipated in wire B will be one-fourth (1/4) that of wire A. Hence, the correct relationship is P = P1/2.

Therefore, option 2 (P = P1/2) is the correct answer.

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