Q: 61 (NDA-II/2009)
question_subject:
Science
question_exam:
NDA-II
stats:
0,1,4,2,1,1,1
keywords:
{'rope': [0, 0, 1, 1], 'tension': [0, 0, 0, 1], 'acceleration': [0, 0, 2, 8], 'mass': [0, 0, 2, 3], 'object': [1, 0, 11, 43], 'kg': [0, 1, 9, 24], 'end': [4, 0, 2, 0]}
To find the tension in the rope, we need to consider the forces acting on the object.
The given problem states that the rope is being pulled upward with an acceleration of 0.30 m/s^2.
We can start by calculating the force required to produce this acceleration using Newton`s second law, F = ma.
The mass of the object is given as 5 kg, and the acceleration is 0.30 m/s^2.
So, the force required is F = 5 kg × 0.30 m/s^2 = 1.5 N.
Since the rope is the only force acting on the object, the tension in the rope must be equal to this force.
Therefore, the tension in the rope is 1.5 N.
Alert - correct answer should be 1.5 N.