A circus performer of mass M is walking along a wire as shown in the figure given below. The tension T in the wire is (g = acceleration due to gravity)

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Q: 58 (NDA-II/2010)
A circus performer of mass M is walking along a wire as shown in the figure given below. The tension T in the wire is (g = acceleration due to gravity)

question_subject: 

Science

question_exam: 

NDA-II

stats: 

0,2,4,3,2,0,1

keywords: 

{'circus performer': [0, 0, 1, 0], 'mg': [1, 0, 4, 6], 'wire': [0, 0, 7, 16], 'performer': [0, 0, 1, 0], 'acceleration': [0, 0, 2, 8], 'gravity': [0, 0, 0, 6], 'figure': [0, 1, 1, 0]}

Option 1: The tension in the wire is approximately Mg.

This option suggests that the tension in the wire is equal to the weight of the performer, which is Mg (mass multiplied by acceleration due to gravity). While this answer seems plausible, it is not entirely accurate. The tension in the wire is not simply equal to the weight of the performer.

Option 2: The tension in the wire is less than Mg.

This option correctly states that the tension in the wire is less than Mg. This is because the performer`s weight is balanced by the tension in the wire. If the tension were equal to the weight, there would be no net force and the performer would not be able to walk along the wire. Therefore, the tension is lower than Mg to allow for some room for balance and movement.

Option 3: The tension in the wire is more than Mg.

This option is incorrect. As mentioned above, the tension in the wire is not more than Mg. It is actually less than Mg to allow for balance and movement.

Option 4: The tension in the wire depends on whether the performer stands on one or two feet.

This option is also incorrect. The tension in the wire is not dependent on whether the performer stands on one or two feet. It

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