Q: 76 (CAPF/2014)
question_subject:
Logic/Reasoning
question_exam:
CAPF
stats:
0,13,11,13,8,3,0
keywords:
{'capital letter': [0, 0, 0, 1], 'capital letters': [0, 0, 0, 1], '21st letter': [0, 0, 0, 1], 'english alphabet': [0, 0, 1, 2], 'many vowels': [0, 0, 0, 1], 'alternate letter': [0, 0, 0, 1], 'letters': [0, 0, 0, 3], 'small letters': [0, 0, 1, 1], 'lower case': [0, 0, 0, 1]}
In this question, we are asked to determine how many vowels will be written in capital letters when every alternate letter of the English alphabet is written in lowercase, with the 21st letter being uppercase and the remaining letters being capitalized.
To solve this, let`s first list out the English alphabet: A, B, C, D, E, F, G, H, I, J, K, L, M, N, O, P, Q, R, S, T, U, V, W, X, Y, Z.
Now, let`s apply the given condition:
A -> a
B -> B
C -> c
D -> d
E -> E
F -> f
G -> g
...
U -> u
V -> V
W -> w
X -> x
Y -> Y
Z -> z
From this, we can see that the vowels A, E, I, O, and U will be written in capital letters. Therefore, the correct answer is 1 (option 1).
Alert - correct answer should be 5.