Each of the 3 persons is to be given some identical items such that product of the numbers of items received by each of the three persons is equal to 30. In how many maximum different ways can this distribution be done?

examrobotsa's picture
Q: 43 (IAS/2007)
Each of the 3 persons is to be given some identical items such that product of the numbers of items received by each of the three persons is equal to 30. In how many maximum different ways can this distribution be done?

question_subject: 

Maths

question_exam: 

IAS

stats: 

0,3,2,2,0,3,0

keywords: 

{'many maximum different ways': [0, 0, 3, 0], 'distribution': [0, 0, 1, 0], 'identical items': [0, 0, 1, 0], 'items': [3, 4, 8, 15], 'numbers': [0, 1, 0, 0], 'persons': [4, 4, 9, 10]}

First, the factors of 30 must be determined. These are 1, 2, 3, 5, 6, 10, 15, and 30. However, since there are only 3 people and we need the product of the numbers of items each person receives to be 30, the highest number of factors we can choose at a time is 3.

We can distribute the items in following methods:

(1, 1, 30), (1, 2, 15), (1, 3, 10), (1, 5, 6), (2, 3, 5)

That being said, order doesn`t matter in this question, meaning (1, 1, 30) is considered the same as (1, 30, 1) and (30, 1, 1). Therefore, option 3: `27` is incorrect as it over-counts the permutations.

Hence, there are 5 ways to distribute the items among the people so the product of the quantities each person receives is 30. But none of the provided options match the correct answer.

Alert - correct answer should be 5.