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Q15
(NDA-II/2014)
Science & Technology › Basic Science (Physics, Chemistry, Biology) › Basic chemical principles
Answer Verified
How many grams of MgC03 contain 24-00 g of oxygen? (The molar mass of MgC03 is 84-30 g mol-1)
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Correct:
A
Explanation
To find the mass of magnesium carbonate (MgCO3) containing 24.00 g of oxygen, we first determine the mass of oxygen in one mole of the compound. MgCO3 contains three oxygen atoms. Given the atomic mass of oxygen is approximately 16.00 g/mol, one mole of MgCO3 contains 48.00 g of oxygen (3 × 16.00 g/mol). The molar mass of MgCO3 is provided as 84.30 g/mol. Using stoichiometry, if 84.30 g of MgCO3 contains 48.00 g of oxygen, then 24.00 g of oxygen (which is exactly half of 48.00 g) will be present in half a mole of the compound. Calculating this gives: (24.00 g / 48.00 g) × 84.30 g = 42.15 g. Therefore, 42.15 g of MgCO3 contains 24.00 g of oxygen.
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