If we plot a graph between volume V and inverse of pressure P (i.e.. -^) for an ideal gas at constant temperature T, the curve so obtained is

examrobotsa's picture
Q: 57 (NDA-II/2016)
If we plot a graph between volume V and inverse of pressure P (i.e.. -^) for an ideal gas at constant temperature T, the curve so obtained is

question_subject: 

Science

question_exam: 

NDA-II

stats: 

0,7,5,7,1,3,1

keywords: 

{'curve': [0, 0, 0, 1], 'graph': [0, 1, 1, 0], 'parabola': [0, 0, 1, 3], 'ideal gas': [0, 0, 0, 1], 'hyperbola': [0, 0, 0, 1], 'straight line': [1, 0, 3, 15], 'inverse': [0, 0, 0, 1], 'circle': [0, 0, 2, 1]}

When we plot a graph between volume (V) and the inverse of pressure (1/P) for an ideal gas at constant temperature, the curve obtained is a straight line. This relationship is known as Boyle`s law. Boyle`s law states that the product of pressure and volume is constant for a fixed amount of gas at a constant temperature. Mathematically, it can be written as P × V = constant.

When we rearrange this equation to isolate volume, we get V = constant / P. This equation represents a hyperbola since the product of pressure and volume is constant. However, if we plot the graph between V and 1/P, the equation becomes V = constant × 1/P, which simplifies to V = constant × (1/P). This equation represents a straight line when plotted on a graph.

Therefore, the correct answer is option 1: a straight line.