The ionization energy of hydrogen atom in the ground state is

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Q: 29 (NDA-II/2017)
The ionization energy of hydrogen atom in the ground state is

question_subject: 

Science

question_exam: 

NDA-II

stats: 

0,3,6,2,3,4,0

keywords: 

{'hydrogen atom': [0, 0, 0, 4], 'ionization energy': [0, 0, 0, 1], 'ground state': [0, 0, 0, 1], 'mev': [0, 0, 0, 2], 'zero': [0, 1, 0, 5], 'joule': [0, 0, 0, 1]}

Option 1 states that the ionization energy of a hydrogen atom in the ground state is 13-6 MeV. This is incorrect. MeV stands for mega-electron volts, which is a unit of energy typically used in nuclear physics. The ionization energy of an atom is usually expressed in electron volts (eV), not MeV.

Option 3 suggests that the ionization energy of a hydrogen atom in the ground state is 13-6 Joule. This is also incorrect because joule is not the commonly used unit for measuring ionization energy. Ionization energy is typically measured in electron volts (eV) or kilojoules per mole (kJ/mol), not joules.

Option 4 states that the ionization energy of a hydrogen atom in the ground state is zero. This is incorrect as well. The ionization energy of a hydrogen atom is not zero, as it requires energy to remove an electron from an atom.

Option 2 is correct. It states that the ionization energy of a hydrogen atom in the ground state is 13-6 eV. This means that it requires an energy of 13.6 electron volts to remove an electron from a hydrogen atom in its ground state. This is a well-established value and

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