To determine the day of the week for March 1, 2002, we can use a method called Zeller`s Congruence. This formula allows us to calculate the day of the week for any given date in the Gregorian calendar.
Zeller`s Congruence uses the following formula:
h = (q + ((13 * (m + 1)) / 5) + K + (K / 4) + (J / 4) - 2J) % 7
Where:
- h is the day of the week (0 = Saturday, 1 = Sunday, 2 = Monday, ..., 6 = Friday)
- q is the day of the month (1, 2, ..., 31)
- m is the month (3 = March, 4 = April, ..., 14 = February)
- K is the year of the century (year % 100)
- J is the zero-based century (actually ? year / 100 ?)
Let`s calculate the values for March 1, 2002, and find out the corresponding day of the week.
q = 1 (March 1)
m = 1 (January)
K = 2 (2002 % 100 = 2)
J = 20 (?2002 / 100? = 20)
Plugging these values into the formula, we get:
h = (1 + ((13 * (1 + 1)) / 5) + 2 + (2 / 4) + (20 / 4) - 2 * 20) % 7
= (1 + (26 / 5) + 2 + 0.5 + 5 - 40) % 7
= (1 + 5.2 + 2 + 0.5 + 5 - 40) % 7
= (13.7 - 40) % 7
= -26.3 % 7
= -26.3 + 7
= -19.3
? 4.7
Since the result is approximately 4.7, we can round it to the nearest whole number, which is 5. Therefore, March 1, 2002, fell on a Friday.
Therefore, Option 2: Friday is the correct answer for the day of the week on March 1, 2002.