Q: 79 (NDA-II/2020)
question_subject:
Science
question_exam:
NDA-II
stats:
0,6,5,1,4,6,0
When a metallic wire with a resistance of 20 is cut into two equal parts, each part will have a resistance of 10. When these two parts are connected in parallel, the total resistance of the parallel combination can be calculated using the formula 1/Rtotal = 1/R1 + 1/R2, where Rtotal is the total resistance and R1 and R2 are the resistances of the two parts.
Substituting the values, we get:
1/Rtotal = 1/10 + 1/10
Combining the fractions, we have:
1/Rtotal = 2/10
Multiplying both sides by 10, we get:
10/Rtotal = 2
Dividing both sides by 2, we get:
Rtotal = 5
Therefore, the resistance of the parallel combination is equal to 5.