The correct answer is option 3, which is 48.
To arrange the 3 boys and 2 girls in a queue with the condition that the 2 girls have to be next to each other, we can treat the 2 girls as a single entity. This means that we have 4 entities to arrange: 3 boys and the "group" of 2 girls.
The 4 entities can be arranged in 4! (4 factorial) ways. However, within the "group" of 2 girls, the girls can be arranged in 2! (2 factorial) ways.
Thus, the total number of ways to arrange them is 4! * 2!, which is equal to 24 * 2 = 48.
Therefore, the correct answer is option 3, which is 48.