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Let`s calculate the marks needed in the third annual examination to have an overall average of 60%.
We are given that there are three annual examinations, each with a total of 500 marks.
To calculate the overall average, we need to consider the weightage of each examination.
Let`s assume the marks obtained in the third annual examination as "x".
The total marks obtained in the first annual examination can be calculated as 45% of 500, which is 0.45 * 500 = 225.
The total marks obtained in the second annual examination can be calculated as 55% of 500, which is 0.55 * 500 = 275.
The total marks obtained in the third annual examination can be calculated as x.
Now, we can calculate the total marks obtained in all three examinations:
225 + 275 + x = total marks
The overall average is desired to be 60%. We can express this as a fraction of 60/100.
The overall average can be calculated using the formula:
(225 + 275 + x) / (3 * 500) = 60/100
Simplifying the equation:
(500 + x) / 1500 = 60/100
Cross-multiplying:
100(500 + x) = 60 * 1500
50000 + 100x = 90000
100x = 90000 - 50000
100x = 40000
x = 40000 / 100
x = 400
Therefore, the student needs to secure 400 marks in the third annual examination to have an overall average of 60%.
The closest option given is 400, which is the correct answer.