A racing car accelerates on a straight road, from rest to a speed of 50 m/s in 25 s. Assuming uniform acceleration of the car throughout, the distance covered in this time will be

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Q: 58 (NDA-I/2016)
A racing car accelerates on a straight road, from rest to a speed of 50 m/s in 25 s. Assuming uniform acceleration of the car throughout, the distance covered in this time will be

question_subject: 

Maths

question_exam: 

NDA-I

stats: 

0,3,13,3,9,3,1

keywords: 

{'uniform acceleration': [0, 0, 0, 5], 'racing car': [0, 0, 0, 1], 'distance': [0, 3, 3, 3], 'speed': [0, 1, 2, 0], 'straight road': [0, 0, 1, 2], 'car': [0, 2, 12, 17]}

In this question, we have a racing car that starts from rest and accelerates to a speed of 50 m/s in 25 seconds. We are asked to find the distance covered by the car in this time.

To solve this problem, we can use the equation of motion: distance = initial velocity * time + (1/2) * acceleration * time^2.

Since the car starts from rest, the initial velocity (u) is 0, and the equation simplifies to: distance = (1/2) * acceleration * time^2.

We are given that the time (t) is 25 seconds and we need to find the distance covered. The only missing variable is the acceleration (a). To find it, we can use the formula: acceleration = change in velocity / time.

The change in velocity (v) is the final velocity (50 m/s) minus the initial velocity (0 m/s), which gives us 50 m/s.

Plugging in these values, we have: acceleration = 50 m/s / 25 s = 2 m/s^2.

Now we can substitute the values of acceleration (2 m/s^2) and time (25 s) back into the equation: distance = (1/2