The square root of the cube of this number is the cube of its square root. It is not 1 and it is less than 6. What is it ?

examrobotsa's picture
Q: 148 (IAS/1994)
The square root of the cube of this number is the cube of its square root. It is not 1 and it is less than 6. What is it ?

question_subject: 

Maths

question_exam: 

IAS

stats: 

0,10,25,10,9,13,3

keywords: 

{'square root': [0, 1, 0, 0], 'cube': [0, 0, 2, 0], 'number': [0, 0, 0, 2]}

The question is asking to find a number which satisfies the condition that the square root of the cube of the number equals the cube of its square root. This condition is true for number 1 as the square root of the cube of 1 is 1 (since 1³=1 and square root of 1 is 1) and the cube of its square root is also 1 (since square root of 1 is 1 and 1³ is also 1). Let`s look at other options:

Option- 2 3: Square root of cube of 3 (3³=27 and √27≈5.20) does not equal the cube of its square root (∛3=1.44 and 1.44³≈3.00)

Option- 3 4: Square root of cube of 4 (4³=64 and √64=8) does not equal the cube of its square root (∛4=1.59 and 1.59³≈4.00)

Option- 4 5: Square root of cube of 5 (5³=125 and √125≈11.18) does not equal the cube of its square root (∛