There are 28 steps in a temple. In the time A, initially at the 28th step, comes down two steps, B, initially at 1 step, goes one step up. If they start simultaneously and keep their speed uniform, then at which step from the bottom will they meet ?

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Q: 101 (CAPF/2014)
There are 28 steps in a temple. In the time A, initially at the 28th step, comes down two steps, B, initially at 1“ step, goes one step up. If they start simultaneously and keep their speed uniform, then at which step from the bottom will they meet ?

question_subject: 

Science

question_exam: 

CAPF

stats: 

0,8,14,3,8,8,3

keywords: 

{'28th step': [0, 0, 0, 1], 'speed uniform': [0, 0, 0, 2], 'steps': [0, 0, 0, 1], 'temple': [1, 0, 0, 0], 'step': [2, 0, 0, 5], '10th': [1, 0, 0, 3], '8th': [1, 0, 0, 2]}

In this problem, we have two individuals, A and B, starting at different steps in a temple. Both individuals are moving at a uniform speed. We need to determine at which step they will meet.

Let`s analyze the situation step by step:

- Initially, A is at the 28th step and comes down two steps. This means A is now at the 26th step.

- Initially, B is at the 1st step and goes one step up. This means B is now at the 2nd step.

Now, let`s observe the movement of both individuals:

- A is moving down at a speed of 2 steps per unit of time.

- B is moving up at a speed of 1 step per unit of time.

Since both individuals are moving at a uniform speed, A will reach the 25th step when B reaches the 3rd step. At this point, they are 22 steps apart.

However, since B is now ahead of A, we need to consider the speed at which they are closing the gap. The relative speed between A and B is 2 steps per unit of time.

To find the number of units of time required for A to catch up with B, we divide the distance between them (22