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Q140
(IAS/1995)
Science & Technology › Basic Science (Physics, Chemistry, Biology) › Quantitative aptitude topics
Answer Verified
A thief running at 8 km/hr is chased by a policeman whose speed is 10 km/hr. If the thief is 100 metres ahead of the policeman, then the time required for the policeman to catch the thief will be
Result
Your answer:
—
·
Correct:
D
Explanation
Compute catch-up using relative speed. Convert units: 100 metres = 0.1 km and speeds are given in km/h, so time in hours is distance (km) divided by relative speed (km/h) [1]. Relative speed = 10 − 8 = 2 km/h. Time = 0.1 km ÷ 2 km/h = 0.05 h, which equals 0.05 × 60 = 3 minutes. This method (using relative speed for two bodies moving in same direction and ensuring consistent units) is standard for such pursuit problems and matches worked examples of similar problems. Hence the policeman catches the thief in 3 minutes.
Sources
- [1] Science-Class VII . NCERT(Revised ed 2025) > Chapter 8: Measurement of Time and Motion > Speed = Total distance covered Total time taken > p. 113
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