Two forces, one of 3 newton and another of 4 newton are applied on a standard 1 kg body, placed on a horizontal and frictionless surface, simultaneously along the x-axis and the y-axis, respectively, as shown below: The magnitude of the resultant acceleration is:

According to Newton's Second Law, the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass (F = ma). When two forces act simultaneously along the x-axis (3 N) and y-axis (4 N), they are perpendicular to each other. The magnitude of the resultant force (R) is calculated using the Pythagorean theorem for vector addition: R = ∑∑(Fx² + Fy²) = ∑∑(3² + 4²) = ∑∑(9 + 16) = ∑∑25 = 5 N. Given the mass (m) of the standard body is 1 kg, the magnitude of the resultant acceleration (a) is found by rearranging the formula to a = F/m. Substituting the values, a = 5 N / 1 kg = 5 m/s². This calculation assumes a frictionless surface, meaning no opposing forces reduce the net force.