Option 1: If we considered Ms. A and Mr. B in the committee, then there would be less possible combinations. However, since Ms. A refuses to be in a committee with Mr. B, this option is invalid.

Option 2: If we had only 12 possible combinations, that would mean either some of the females or males are not considered. Since Ms. A and Mr. B can`t be in the same committee and there are 5 males and 3 females, we expect more than 12 combinations.

Option 3: Similarly to option 2, with 13 possible combinations some potential combinations are left out which would mean not all of the females and males are considered.

Option 4: There are 5 males and since Ms. A won`t team with Mr. B, there are 2 other females that could. So combinations considering other males are 5*2=10. The combination of Ms. A with the remaining 4 males gives us another 4 possibilities. So, total possible combinations are 10+4=14. Hence, correct answer is 14.