The width of a rectangle is 4x which is only 25% of its length. What are the area and the perimeter of the rectangle respectively ?

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Q: 119 (CAPF/2009)
The width of a rectangle is 4x which is only 25% of its length. What are the area and the perimeter of the rectangle respectively ?

question_subject: 

Science

question_exam: 

CAPF

stats: 

0,2,3,1,1,1,2

keywords: 

{'perimeter': [0, 1, 1, 0], 'rectangle': [0, 1, 0, 1], 'width': [0, 2, 1, 1], '16x unit': [0, 0, 1, 0], 'area': [0, 0, 0, 1], '4x': [0, 0, 1, 0], 'squnit': [0, 0, 1, 0], 'length': [0, 0, 1, 0]}

To find the area of a rectangle, we multiply its length and width.

Given that the width of the rectangle is 4x and it is 25% of the length, we can say that the length is 4 times the width, or 16x.

So, the area of the rectangle is (4x) * (16x) = 64x^2 square units.

To find the perimeter of a rectangle, we add the lengths of all its sides.

The length of two opposite sides is 16x, and the width of the other two opposite sides is 4x.

Therefore, the perimeter of the rectangle is (16x + 16x + 4x + 4x) = 40x units.

So, the correct answer is option 4 – the area of the rectangle is 64x^2 square units and the perimeter is 40x units.