In the relation a = bt + X, a and X are measured in metre (m) and t is measured in second (s). The SI unit of b must be

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Q: 67 (NDA-II/2009)
In the relation a = bt + X, a and X are measured in metre (m) and t is measured in second (s). The SI unit of b must be

question_subject: 

Science

question_exam: 

NDA-II

stats: 

0,2,2,0,2,0,2

keywords: 

{'si unit': [0, 0, 1, 5], 'metre': [0, 3, 4, 3], 'relation': [1, 0, 2, 5], 'ms': [0, 0, 2, 1]}

In the given relation a = bt + X, a represents a physical quantity measured in metres (m), t represents time measured in seconds (s), and X represents a constant term in metres (m).

To determine the SI unit of b, we can rearrange the equation to isolate b:

a = bt + X

a - X = bt

b = (a - X) / t

The SI unit of b can be found by examining the units of a, X, and t in the equation.

The unit of a is metres (m).

The unit of X is also metres (m).

The unit of t is seconds (s).

By substituting these units into the equation, we have:

b = (m - m) / s

b = 0 / s

b = 0

Therefore, the SI unit of b is 0.

Alert - correct answer should be "0"