Consider the following number : n = [(6374)1793x(625)3]7x(313)49] Which one of the following is the digit at the unit place of n ?

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Q: 118 (CAPF/2017)
Consider the following number : n = [(6374)1793x(625)3]7x(313)49]
Which one of the following is the digit at the unit place of n ?

question_subject: 

General Knowledge

question_exam: 

CAPF

stats: 

0,5,11,5,4,3,4

keywords: 

{'digit': [0, 0, 0, 2], 'number': [0, 0, 0, 2], 'unit place': [0, 0, 0, 1]}

The given number is expressed as a product of several large numbers raised to different powers. To find the digit at the unit place of the number, we need to determine the units digit of each component and then multiply them together.

Let`s analyze each term separately:

1) (6374)1793: The units digit of 6374 is 4. When it is raised to an odd power (1793 is odd), the units digit remains the same. Therefore, the units digit of this term is 4.

2) (625)3: The units digit of 625 is 5. When it is raised to any power, the units digit remains 5. Therefore, the units digit of this term is 5.

3) (313)49: The units digit of 313 is 3. When it is raised to any power, the units digit remains 3. Therefore, the units digit of this term is 3.

Now, let`s multiply the units digits together: 4 x 5 x 3 = 60. The units digit of the product is 0.

Therefore, the correct option is 1) 0, which represents the digit at the unit place of the given number.

Note: It`s important