Q: 146 (IAS/2010)
question_subject:
Maths
question_exam:
IAS
stats:
0,11,9,1,3,5,11
keywords:
{'equal marks': [0, 0, 2, 0], 'questions': [2, 0, 5, 3], 'test': [2, 2, 8, 3], 'full marks': [0, 0, 2, 0], 'number': [0, 0, 0, 2], 'candidate': [1, 0, 0, 0]}
Let the total number of questions in the test be x. As the candidate attempted 12 questions, he left out (x - 12) questions.
As he secured full marks in all 12 questions attempted, his total score from these questions is 12 (assuming each question carries 1 mark).
Let the marks for each question be m. Then, the total marks in the test is x m.
As the candidate obtained 60% in the test, his total score is 0.6 times the total marks in the test. Therefore, we can write:
12m + (x - 12) * 0 = 0.6 * xm
Simplifying this equation, we get:
12m = 0.6xm
Dividing both sides by 0.6m, we get:
20 = x
Therefore, the total number of questions in the test is 20. The correct answer is option (D) 20.