A is the smallest positive integer which when divided by 9 and 12 leaves remainder 8. B is the smallest positive integer which when divided by 9 and 12 leaves remainder 5. Which one of the following is the value of A - B ?

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Q: 120 (CAPF/2020)
A is the smallest positive integer which when divided by 9 and 12 leaves remainder 8. B is the smallest positive integer which when divided by 9 and 12 leaves remainder
5.
Which one of the following is the value of A - B ?

question_subject: 

Science

question_exam: 

CAPF

stats: 

0,6,4,6,3,1,0

keywords: 

{'smallest positive integer': [0, 0, 0, 1], 'leaves remainder': [0, 0, 0, 1], 'value': [0, 0, 1, 0]}

To find the value of A - B, we need to first find the values of A and B individually.

A is the smallest positive integer which when divided by 9 and 12 leaves a remainder of 8. This means that A is a number that is 8 more than a multiple of both 9 and 12. To find the smallest positive integer that satisfies this condition, we can find the least common multiple (LCM) of 9 and 12, and then add 8 to it.

The LCM of 9 and 12 is 36. Adding 8 to this gives us A = 36 + 8 = 44.

Similarly, B is the smallest positive integer which when divided by 9 and 12 leaves a remainder of 5. This means that B is a number that is 5 more than a multiple of both 9 and 12. Again, we can find the LCM of 9 and 12, and add 5 to it to find the value of B.

The LCM of 9 and 12 is 36. Adding 5 to this gives us B = 36 + 5 = 41.

Now, we can subtract B from A to find