Let`s denote the number of 2 coins as x, and the number of 5 coins as y. According to the question, we have two equations: x + y = 100 and 2x + 5y = 320.

If we solve these simultaneously:

- Option 1 suggests that there are 40 coins of 2. If we substitute x=40 into the equations, we get y=60 for the first equation and y=32 for the second, which is inconsistent. Hence, option 1 cannot be correct.

- Option 2 suggests that there are 50 coins of 2. If we substitute x=50 into the equations, we get y=50 for the first equation and y=40 for the second. They aren`t equal, hence option 2 cannot be correct either.

- Option 3 suggests that there are 60 coins of 2. If we substitute x=60, we get y=40 for the first equation and y=40 for the second. Both equations are consistent with y=40, so option 3 is indeed correct.

- Option 4 suggests that there are 70 coins of 2. If we substitute x=70 into the equations, we get y=30 for the first