Q: 16 (NDA-II/2022)
question_subject:
Science
question_exam:
NDA-II
stats:
0,5,5,5,1,1,3
To find the power of the bulb, we can use the formula P = IV, where P is the power, I is the current, and V is the voltage.
In this case, the current drawn by the bulb is 600 mA, which is equivalent to 0.6 A (since 1 A = 1000 mA). The voltage supplied by the generator is 220 V.
Now, substituting these values in the formula, we get P = 0.6 A * 220 V = 132 W.
Therefore, the power of the bulb is 132 W.
Alert - correct answer should be 132 W.