To find the power of the bulb, we can use the formula P = IV, where P is the power, I is the current, and V is the voltage.

In this case, the current drawn by the bulb is 600 mA, which is equivalent to 0.6 A (since 1 A = 1000 mA). The voltage supplied by the generator is 220 V.

Now, substituting these values in the formula, we get P = 0.6 A * 220 V = 132 W.

Therefore, the power of the bulb is 132 W.

Alert - correct answer should be 132 W.