A rectangle has a perimeter of 50 meters. If its length is 13 metres more than its breadth, then its area is

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Q: 148 (IAS/1996)
A rectangle has a perimeter of 50 meters. If its length is 13 metres more than its breadth, then its area is

question_subject: 

Maths

question_exam: 

IAS

stats: 

0,5,9,2,6,5,1

keywords: 

{'rectangle': [0, 1, 0, 1], 'perimeter': [0, 1, 1, 0], 'length': [0, 0, 1, 0], 'metres': [0, 1, 1, 0], 'meters': [0, 1, 0, 2], 'area': [0, 0, 0, 1], 'breadth': [1, 2, 1, 1]}

The perimeter of a rectangle is given by the formula 2*(length+breadth). Here, it`s 50 meters. The problem also states that length is 13 meters more than the breadth. If we let the breadth be `x`, then the length becomes `x+13`. Substituting these into the perimeter formula, we get 2*(x+(x+13))=50. Solving this equation gives x=12.

The area of a rectangle is calculated as length*breadth. Substituting our calculated values, we get (12+13)*12=300 m2.

Option 1, 124 m2, is incorrect as it doesn`t match our calculated area. Option 2, 144 m2, also doesn`t match. Option 4, 104 m2, is even further from our calculation. Therefore, none of these options are correct.

Alert - correct answer should be 300 m2. The provided correct answer, option 3, 114 m2, is also incorrect.

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