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The total time for which A and B walk is from 7 a.m. to 12:30 p.m. which is 5.5 hrs. The speed of A is 3 km/hr and of B is 2.5 km/hr. So, the distance covered by A in 5.5 hours will be 3*5.5 = 16.5 km and the distance covered by B will be 2.5*5.5 = 13.75 km. The perimeter of the rectangular field is 2*(400+300) m = 1400 m = 1.4 km. So, A will complete 16.5/1.4 = 11.78 ~ 11 rounds; similarly, B will complete 13.75/1.4 = 9.82 ~ 9 rounds. The difference between their rounds is 11-9 = 2 times. So, they will cross each other 2 times.
Option 1 `Not even once` and Option 4 `Thrice` are incorrect because they do not align with the calculations. Option 3 `Twice` is the correct answer as per the calculation, but option 2 `Once` is not correct because