A ball is thrown vertically upward from the ground with a speed of 25-2 m/s. The ball will reach the highest point of its journey in

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Q: 23 (NDA-II/2016)
A ball is thrown vertically upward from the ground with a speed of 25-2 m/s. The ball will reach the highest point of its journey in

question_subject: 

Science

question_exam: 

NDA-II

stats: 

0,1,3,1,2,1,0

keywords: 

{'highest point': [0, 0, 0, 1], 'ball': [1, 3, 13, 12], 'speed': [0, 1, 2, 0], 'ground': [2, 1, 4, 17], 'journey': [0, 1, 3, 2]}

The correct option is option 3, which states that the ball will reach the highest point of its journey in 2.57 seconds.

When the ball is thrown vertically upward from the ground, it will experience a constant acceleration due to gravity, which is approximately 9.8 m/s^2 (ignoring air resistance). This acceleration is always directed downwards, opposing the ball`s upward motion.

To determine the time taken by the ball to reach the highest point, we can use the equation of motion:

vf = vi + at,

where vf is the final velocity, vi is the initial velocity, a is the acceleration, and t is the time.

In this case, the final velocity of the ball at the highest point is 0 m/s because it momentarily comes to a stop before falling back down. The initial velocity (vi) is 25-2 m/s (the given value).

Setting the equations equal to each other, we have:

0 = 25-2 - 9.8t

Rearranging, we find:

9.8t = 25-2

Solving for t, we get:

t ≈ (25-2) / 9.8 ≈ 2.57 seconds

Therefore, option

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