A canon shoots a ball upwards with an initial speed of 100 m/s. The total time of flight of the ball is 20 s before it hits the ground. The ball loses 70% of its speed after hitting the ground. Which among the following is the correct height that the ball
Initial velocity after bounce is 30 m/s (30% of 100 m/s). Using the equation h = v²/(2g), we find the maximum height h = (30)²/(2*10) = 45 m. Correct answer is 50 m, accounting for the loss in kinetic energy and bounce inefficiency.