During explosion of gunpowder, which of the following gases are evolved in the proportion of 1:3?

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Q: 75 (NDA-II/2011)
During explosion of gunpowder, which of the following gases are evolved in the proportion of 1:3?

question_subject: 

Science

question_exam: 

NDA-II

stats: 

0,62,82,30,29,62,23

keywords: 

{'gases': [0, 0, 5, 12], 'gunpowder': [0, 0, 0, 1], 'nitrogen': [1, 1, 0, 2], 'carbon dioxide': [2, 0, 5, 6], 'explosion': [0, 1, 1, 1], 'oxygen': [3, 0, 1, 0], 'proportion': [1, 1, 2, 8]}

Option 1: Oxygen : Nitrogen

This option is incorrect. Oxygen and nitrogen are not evolved in the proportion of 1:3 during the explosion of gunpowder.

Option 2: Nitrogen : Oxygen

This option is incorrect. Nitrogen and oxygen are not evolved in the proportion of 1:3 during the explosion of gunpowder.

Option 3: Nitrogen : Carbon dioxide

This option is correct. During the explosion of gunpowder, nitrogen and carbon dioxide gases are evolved in the proportion of 1:3. This means that for every 1 molecule of nitrogen gas, 3 molecules of carbon dioxide gas are produced.

Option 4: Carbon dioxide : Nitrogen

This option is incorrect. While both carbon dioxide and nitrogen gases are involved in the explosion of gunpowder, they are not evolved in the proportion of 1:3.

Therefore, the correct answer is option 3.