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Q75
(NDA-II/2011)
Science & Technology › Basic Science (Physics, Chemistry, Biology) › Applied everyday chemistry
Answer Verified
During explosion of gunpowder, which of the following gases are evolved in the proportion of 1:3?
Result
Your answer:
—
·
Correct:
C
Explanation
The correct answer is Option 3: Nitrogen : Carbon dioxide.
Gunpowder, or black powder, typically consists of Potassium Nitrate (KNO₃), Sulfur (S), and Charcoal (C). While the exact reaction can vary depending on the ratio of ingredients, a standard balanced chemical equation for the combustion of gunpowder is:
10KNO₃ + 3S + 8C → 2K₂CO₃ + 3K₂SO₄ + 6CO₂ + 5N₂
However, in simplified or specific theoretical models of gunpowder explosion, the reaction is often represented as:
2KNO₃ + S + 3C → K₂S + N₂ + 3CO₂
- In this reaction, one mole of Nitrogen (Nâ‚‚) is produced for every three moles of Carbon dioxide (COâ‚‚).
- This results in a molar ratio of 1:3 between Nitrogen and Carbon dioxide.
Options 1 and 2 are incorrect because free Oxygen is consumed as an oxidizer rather than evolved as a major product. Option 4 is incorrect as it reverses the required 1:3 proportion.
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