In a Chloropropane molecule with the molecular formula C3H7Cl, let`s analyze the number of covalent bonds.

First, we need to determine the number of valence electrons for each atom involved. Carbon (C) has 4 valence electrons, Hydrogen (H) has 1 valence electron, and Chlorine (Cl) has 7 valence electrons.

Next, we need to assemble the molecular formula and count the number of valence electrons used. C3H7Cl indicates that we have 3 Carbon atoms, 7 Hydrogen atoms, and 1 Chlorine atom.

For each Carbon atom, it forms 4 covalent bonds by sharing its 4 valence electrons. So, 3 Carbon atoms would contribute 3 x 4 = 12 covalent bonds.

For each Hydrogen atom, it forms 1 covalent bond by sharing its 1 valence electron. So, 7 Hydrogen atoms would contribute 7 x 1 = 7 covalent bonds.

For the Chlorine atom, it forms 1 covalent bond by sharing its 7 valence electrons.

Adding up the covalent bonds formed by each atom, we have 12 + 7