NaOH + HCl ---> NaCl + H2O In the above chemical reaction :

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Q: 22 (CDS-II/2013)
NaOH + HCl ---> NaCl + H2O
In the above chemical reaction :

question_subject: 

Science

question_exam: 

CDS-II

stats: 

0,12,16,2,9,5,12

keywords: 

{'above chemical reaction': [0, 0, 0, 1], 'hcl': [0, 0, 2, 0], 'nacl': [0, 0, 1, 0], 'chlorine': [8, 2, 8, 9], 'sodium': [10, 2, 12, 23], 'naoh': [0, 0, 1, 9], 'hydrogen': [0, 0, 1, 3], 'oxygen': [3, 0, 1, 0], 'h2o': [0, 0, 2, 3]}

In the given chemical reaction, NaOH (sodium hydroxide) reacts with HCl (hydrochloric acid) to produce NaCl (sodium chloride) and H2O (water). The correct answer is option 4, none of them are oxidized or reduced.

In a redox (oxidation-reduction) reaction, there is a transfer of electrons between atoms or molecules. Oxidation refers to the loss of electrons, while reduction refers to the gain of electrons. These reactions are characterized by changes in the oxidation states of the elements involved.

In this reaction, neither sodium nor hydrogen undergoes a change in oxidation state. Sodium starts with an oxidation state of +1 in NaOH and ends with +1 in NaCl. Hydrogen starts with an oxidation state of +1 in HCl and ends with +1 in H2O. Since there is no change in oxidation state for any of the elements, it can be concluded that neither sodium nor hydrogen is oxidized or reduced.

Therefore, the correct answer is option 4, none of them are oxidized or reduced.