A piece of ice, 100 g in mass is kept at 0 C. The amount of heat it requires to melt at 0 C is (take latent heat of melting of ice to be 33 3.6 J/g):

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Q: 35 (CDS-I/2016)
A piece of ice, 100 g in mass is kept at 0 °C. The amount of heat it requires to melt at 0 °C is (take latent heat of melting of ice to be 33
3.6 J/g):

question_subject: 

Science

question_exam: 

CDS-I

stats: 

0,14,13,4,5,14,4

keywords: 

{'melting': [0, 0, 0, 1], 'ice': [0, 0, 1, 0], 'mass': [0, 0, 2, 3], 'heat': [10, 3, 13, 46], 'latent heat': [0, 0, 1, 3], 'amount': [1, 2, 4, 9]}

Option 1: 750.6 J

This option is incorrect. We are given the mass of the ice as 100 g and the latent heat of melting of ice as 33.6 J/g. To find the amount of heat required to melt the ice, we multiply the mass of the ice by the latent heat of melting. So, the correct calculation would be:

100 g * 33.6 J/g = 3360 J.

Option 2: 83.4 J

This option is incorrect. As mentioned above, to find the amount of heat required to melt the ice, we multiply the mass of the ice (100 g) by the latent heat of melting (33.6 J/g). So, the correct calculation would be:

100 g * 33.6 J/g = 3360 J.

Option 3: 33360 J

This option is correct. We are given the mass of the ice as 100 g and the latent heat of melting of ice as 33.6 J/g. To find the amount of heat required to melt the ice, we multiply the mass of the ice by the latent heat of melting. So, the correct calculation would be:

100 g * 33