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Q12 (CAPF/2013) Science & Technology › Basic Science (Physics, Chemistry, Biology) › Quantitative aptitude topics Answer Verified

Two cars are moving in the same direction with a speed of 45 km/hr and a distance of 10 km separates them. If a car coming from the opposite direction meets these two cars at an interval of 6 minutes, its speed would be

Result
Your answer: —  Â·  Correct: B
Explanation

To solve this, we use the concept of relative speed. Two cars (A and B) are moving in the same direction at 45 km/hr, separated by 10 km. A third car (C) is moving in the opposite direction with speed 'v'. When objects move in opposite directions, their relative speed is the sum of their individual speeds. Thus, the relative speed of car C with respect to car A or B is (v + 45) km/hr. The problem states car C meets the two cars at an interval of 6 minutes (which is 0.1 hours). Using the formula Distance = Relative Speed × Time, we have 10 = (v + 45) × 0.1. Solving for v: 10 / 0.1 = v + 45, which gives 100 = v + 45. Therefore, v = 55 km/hr. This aligns with the principle that relative velocity is the difference or sum depending on direction.

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