A car moving with a speed of 12 m/s is subjected to brakes which produces a deceleration of 6 m/s². The car takes 2 s to stop after the application of brakes. What is the distance covered by the car after the application of brakes?
Using the equation of motion: s = ut + (1/2)at². Here, u = 12 m/s, a = -6 m/s², t = 2 s. So, s = 12*2 + 0.5*(-6)*(2²) = 24 - 12 = 12 m, thus the correct answer is 12 m.