A simple circuit contains a 12 V battery and a bulb having 24 ohm resistance. When you turn on the switch, the ammeter connected in the circuit would read

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Q: 43 (NDA-I/2016)
A simple circuit contains a 12 V battery and a bulb having 24 ohm resistance. When you turn on the switch, the ammeter connected in the circuit would read

question_subject: 

Science

question_exam: 

NDA-I

stats: 

0,27,17,27,13,4,0

keywords: 

{'simple circuit': [0, 0, 0, 1], 'circuit': [0, 0, 1, 3], 'bulb': [3, 0, 1, 5], 'ammeter': [0, 0, 0, 1], 'switch': [0, 0, 2, 1], 'ohm resistance': [0, 0, 0, 2], '2a': [0, 0, 0, 1]}

In this simple circuit, we have a 12 V battery and a bulb with a resistance of 24 ohms. When the switch is turned on, the ammeter connected in the circuit will read a certain value.

To determine the current flowing through the circuit (which is what the ammeter measures), we can use Ohm`s Law: V = I * R, where V is the voltage, I is the current, and R is the resistance.

In this case, the voltage of the battery is 12 V, and the resistance of the bulb is 24 ohms. Plugging these values into Ohm`s Law, we can calculate the current:

12 V = I * 24 ohms

Solving for I, we get:

I = 12 V / 24 ohms

Simplifying, we find that the current flowing through the circuit is 0.5 A.

Therefore, the correct answer is option 1: 0-5 A. The ammeter will read a value between 0 and 5 A.