Match List I with List II and select the correct answer using the code given below the Lists: List I (Element) A. Boron B. Nitrogen C. Oxygen D. Neon List II (Unpaired electron) 1. Zero 2. Two 3. One 4. Three
Boron has three valence electrons, nitrogen has five, oxygen has six but needs two more for a complete shell, and neon has a full octet with zero unpaired electrons. Thus, boron has three unpaired electrons, nitrogen one, oxygen two, and neon zero.